Planetary Industry: Difference between revisions

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For more information on Links and Routing see [[Setting up a planetary colony#Intraplanetary Logistics|Intraplanetary Logistics]]. To learn about what to do next, keep reading!

==== Links resource usage ====

The scale of the infrastructure increases linearly with the radius of the planet. As such, the distance between two factories also increases linearly.

* The Minimum Link distance (ml) on a planet of radius r is : ml = 0,012008578×r (with ml and r in km). This the distance between the center of two pins.

* The PG cost of a link of distance l is : p(l) = 10+0.15×l

* The CPU cost of a link of distance l is : c(l) = 15+0.2×l

We can then express the links on a planet as ''n'' the number of started links and ''k'' the ratio of total length compared to minimum length, <math>k=\sum_{link} link.length/ml </math>

* if the infrastructures are only a launchpad and 6 high-tech production plants (htpp), with the launchpad in the middle, we have 6 links and total 6 minimal segments

* if we add 12 htpp around the 6 existing, half of them will require 2 segments (those just after another htpp) and the other half will require <math>\sqrt 3</math> segments. Therefore the total number of links is 18 , the total length is <math>6×1+6×2+6×\sqrt 3 = 28.4</math> minimal segments.

Once this is done, we have the cost of links on a planet depending on those values and ''r'' the radius of that planet

* PG cost p(r,n,k) = 10×n+0,001801287×r×k

* CPU cost c(r,n,k) = 15×n+0,002401716×r×k

=== Industry ===

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 For more information on Links and Routing see [[Setting up a planetary colony#Intraplanetary Logistics|Intraplanetary Logistics]]. To learn about what to do next, keep reading!
+==== Links resource usage ====
+The scale of the infrastructure increases linearly with the radius of the planet. As such, the distance between two factories also increases linearly.
+* The Minimum Link distance (ml) on a planet of radius r is : ml = 0,012008578×r (with ml and r in km). This the distance between the center of two pins.
+* The PG cost of a link of distance l is : p(l) = 10+0.15×l
+* The CPU cost of a link of distance l is : c(l) = 15+0.2×l
+We can then express the links on a planet as ''n'' the number of started links and ''k'' the ratio of total length compared to minimum length, <math>k=\sum_{link} link.length/ml </math>
+* if the infrastructures are only a launchpad and 6 high-tech production plants (htpp), with the launchpad in the middle, we have 6 links and total 6 minimal segments
+* if we add 12 htpp around the 6 existing, half of them will require 2 segments (those just after another htpp) and the other half will require <math>\sqrt 3</math> segments. Therefore the total number of links is 18 , the total length is <math>6×1+6×2+6×\sqrt 3 = 28.4</math> minimal segments.
+Once this is done, we have the cost of links on a planet depending on those values and ''r'' the radius of that planet
+* PG cost p(r,n,k) = 10×n+0,001801287×r×k
+* CPU cost c(r,n,k) = 15×n+0,002401716×r×k
 === Industry ===