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Latest comment: 25 November 2013 by Rain kaessinde
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m Fix User: link |
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S(n) = 0.5^( (n-1)^2 / LN(140) ) | S(n) = 0.5^( (n-1)^2 / LN(140) ) | ||
-- [[User|Naara elein]], 23:07, 4 May 2013 (UTC) | -- [[User:Naara elein|Naara elein]], 23:07, 4 May 2013 (UTC) | ||
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I also reset the penalty formula in terms of a zero-based index and changed/expanded the accompanying text accordingly. This eliminates a set of nested parentheses and reduces the visual complexity of the expression, which is a virtue when writing math in plain text. | I also reset the penalty formula in terms of a zero-based index and changed/expanded the accompanying text accordingly. This eliminates a set of nested parentheses and reduces the visual complexity of the expression, which is a virtue when writing math in plain text. | ||
-- [[User:Rain kaessinde|Rain]] ([[User talk:Rain kaessinde|talk]]) 18:35, 25 November 2013 (UTC) | -- [[User:Rain kaessinde|Rain kaessinde]] ([[User talk:Rain kaessinde|talk]]) 18:35, 25 November 2013 (UTC) | ||
Latest revision as of 16:57, 20 November 2021
2.22292081^2 is an approximation of LN(140)
The formula should be:
S(n) = 0.5^( (n-1)^2 / LN(140) )
-- Naara elein, 23:07, 4 May 2013 (UTC)
Changed the penalty formula to a base-e form, which matches in-game values to the full displayed precision of 10^-10. Note that the decay constant of 2.67 is an exact number, not a rounded decimal!
I also reset the penalty formula in terms of a zero-based index and changed/expanded the accompanying text accordingly. This eliminates a set of nested parentheses and reduces the visual complexity of the expression, which is a virtue when writing math in plain text.