Difference between revisions of "Talk:Jump clones"
John Haldane (talk | contribs) (Created page with 'Isn't there a second company that we have JC status with?') |
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Isn't there a second company that we have JC status with? | Isn't there a second company that we have JC status with? | ||
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+ | == Connections counts for your own standings == | ||
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+ | Someone recently told me that when grinding up one's own standings with an NPC corporation, an unmodified standing of 8.0 or higher is needed, and that Connections doesn't help with this. However, I have now observed that my alt, Leonard Chong, has unmodified standings of 7.75 with Pator Tech School, that Connections 3 raises this to 8.02, and my alt was able to install a jump clone at a Pator Tech station without any problems. So, if you're grinding your own standings with an NPC corp to get jump clones of your own, then Connections will help you. | ||
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+ | It is not clear to me, though, whether or not Connections would help if a player doesn't have standings with an NPC corp, but his/her player corporation does. I'm guessing it doesn't, but I haven't tested it. | ||
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+ | --[[User:Seamus donohue|Seamus donohue]] 07:30, 1 January 2010 (UTC) |
Revision as of 07:30, 1 January 2010
Isn't there a second company that we have JC status with?
Connections counts for your own standings
Someone recently told me that when grinding up one's own standings with an NPC corporation, an unmodified standing of 8.0 or higher is needed, and that Connections doesn't help with this. However, I have now observed that my alt, Leonard Chong, has unmodified standings of 7.75 with Pator Tech School, that Connections 3 raises this to 8.02, and my alt was able to install a jump clone at a Pator Tech station without any problems. So, if you're grinding your own standings with an NPC corp to get jump clones of your own, then Connections will help you.
It is not clear to me, though, whether or not Connections would help if a player doesn't have standings with an NPC corp, but his/her player corporation does. I'm guessing it doesn't, but I haven't tested it.
--Seamus donohue 07:30, 1 January 2010 (UTC)