Planetary Industry: Difference between revisions

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The scale of the infrastructure increases linearly with the radius of the planet. As such, the distance between two factories also increases linearly. After experimental testing,

* The Minimum Link distance (ml) on a planet of radius r is : ml = 0,012008578×r (with ml and r in km). This the distance between the center of two pins.

* The Minimum Link distance (ml) on a planet of radius r is : ml(r) = 0,012008578×r (with ml and r in km). This the minimal distance between the center of two pins.

* The PG cost of a link of distance l is : p(l) = 10+0.15×l

* The CPU cost of a link of distance l is : c(l) = 15+0.2×l

We can then express the links on a planet as ''n'' the number of started links and ''k'' the ratio of total length compared to minimum length, <math>k=\sum_{link} link.length/ml </math>. Basically, k is the number of minimal size segments ~~we use~~

===== Links usage of a plan =====

We can then express the links of a planetary installation independently of the planet size, as the couple (n,k) with

* ''n'' the number of started links and

* ''k'' the ratio of total length compared to minimum length, <math>k=\sum_{link} link.length/ml </math>.

Basically, n is the number of real links, while k is the number of minimal size segments the links run over.

* if the infrastructures are only a launchpad and 6 high-tech production plants (HP), with the launchpad in the middle, we have 6 links and total 6 minimal segments

* if we add 12 HP around the 6 existing

** if we link them directly to the launchpad, half of them will require 2 segments (those just after another HP) and the other half will require <math>\sqrt 3</math> segments. Therefore the total number of links is 18 , the total length is <math>6×1+6×2+6×\sqrt 3 = 28.4</math> minimal segments.

** if we link them directly to the launchpad, half of them will require 2 segments (those just after another HP) and the other half will require <math>\sqrt 3</math> segments. Therefore the total number of links (n) is 18 , the total length (k) is <math>6×1+6×2+6×\sqrt 3 = 28.4</math> minimal segments.

** if we link them to the closest HP, then we add one minimal segment per new HP, total length is 18

** if we link them to the closest HP, then we add one minimal segment per new HP, total length is 18 so n=k=18.

===== Plan consumption per planet =====

Once this is done, we have the cost of links on a planet depending on those values and ''r'' the radius of that planet

* PG cost p(r,n,k) = 10×n+0,001801287×r×k

* CPU cost c(r,n,k) = 15×n+0,002401716×r×k

Then we can add the (constant) pins usage to those values.

=== Industry ===

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 The scale of the infrastructure increases linearly with the radius of the planet. As such, the distance between two factories also increases linearly. After experimental testing,
-* The Minimum Link distance (ml) on a planet of radius r is : ml = 0,012008578×r (with ml and r in km). This the distance between the center of two pins.
+* The Minimum Link distance (ml) on a planet of radius r is : ml(r) = 0,012008578×r (with ml and r in km). This the minimal distance between the center of two pins.
 * The PG cost of a link of distance l is : p(l) = 10+0.15×l
 * The CPU cost of a link of distance l is : c(l) = 15+0.2×l
-We can then express the links on a planet as ''n'' the number of started links and ''k'' the ratio of total length compared to minimum length, <math>k=\sum_{link} link.length/ml </math>. Basically, k is the number of minimal size segments we use
+===== Links usage of a plan =====
+We can then express the links of a planetary installation independently of the planet size, as the couple (n,k) with
+* ''n'' the number of started links and
+* ''k'' the ratio of total length compared to minimum length, <math>k=\sum_{link} link.length/ml </math>.
+Basically, n is the number of real links, while k is the number of minimal size segments the links run over.
 * if the infrastructures are only a launchpad and 6 high-tech production plants (HP), with the launchpad in the middle, we have 6 links and total 6 minimal segments
 * if we add 12 HP around the 6 existing
-** if we link them directly to the launchpad, half of them will require 2 segments (those just after another HP) and the other half will require <math>\sqrt 3</math> segments. Therefore the total number of links is 18 , the total length is <math>6×1+6×2+6×\sqrt 3 = 28.4</math> minimal segments.
+** if we link them directly to the launchpad, half of them will require 2 segments (those just after another HP) and the other half will require <math>\sqrt 3</math> segments. Therefore the total number of links (n) is 18 , the total length (k) is <math>6×1+6×2+6×\sqrt 3 = 28.4</math> minimal segments.
-** if we link them to the closest HP, then we add one minimal segment per new HP, total length is 18
+** if we link them to the closest HP, then we add one minimal segment per new HP, total length is 18 so n=k=18.
+===== Plan consumption per planet =====
 Once this is done, we have the cost of links on a planet depending on those values and ''r'' the radius of that planet
 * PG cost p(r,n,k) = 10×n+0,001801287×r×k
 * CPU cost c(r,n,k) = 15×n+0,002401716×r×k
+Then we can add the (constant) pins usage to those values.
 === Industry ===