Warp

Time taken to warp

It is possible to work out how long it should take for a ship to complete warp (once it enters warp) based on formulae released by CCP.

Warp consists of 3 stages:

1. Acceleration
2. Cruising
3. Deceleration

Calculating the time taken to warp is done by calculating the time spent in each of these phases and adding them together. This requires calculating acceleration and deceleration time first, followed by cruise time.

Total time in warp is given by:

[math]\pagecolor{Black}\color{White}t_{total} = t_{accel} + t_{decel} + t_{cruise}[/math]

Acceleration

The formulae

CCP provided formulae for both distance traveled and velocity reached after t seconds of acceleration. If d is distance in meters, v is speed in meters per second, k is a (sort of) constant defined as the warp speed (in AU/s) and a = 149,597,870,700 meters (1 AU).

[math]\pagecolor{Black}\color{White} \begin{align} d & = e^{kt} \\ v & = k*e^{kt}\\ v_{max} & = k * a\\ \end{align} [/math]

Distance

To calculate distance traveled while accelerating

[math]\pagecolor{Black}\color{White} \begin{align} d & = e^{kt} \\ v & = k*e^{kt}\\ & = k*d\\ \therefore d & = \frac{v}{k} \end{align} [/math]

The distance covered while accelerating to v_warp is

[math]\pagecolor{Black}\color{White} \begin{align} d_{accel} & = \frac{v_{warp}}{k} & = \frac{k*a}{k} & = a \end{align} [/math]

This means that every ship covers exactly 1 AU while accelerating to its maximum warp speed.

Time

To calculate the time spent accelerating to warp speed, the equation for v should be rearranged to be in terms of t, and then solved for the case of v being equal to the warp speed (in m/s)

[math]\pagecolor{Black}\color{White} \begin{align} v & = k*e^{kt}\\ \frac{v}{k} & = e^{kt}\\ kt & = \ln{(\frac{v}{k})}\\ t & =\frac{\ln{(\frac{v}{k})}}{k}\\ \end{align} [/math]

We want to find the time taken to maximum warp:

[math]\pagecolor{Black}\color{White} \begin{align} v_{warp} & = k * a\\ t_{accel} & = \frac{\ln{(\frac{v_{warp}}{k})}}{k}\\ & = \frac{\ln{(\frac{k*a}{k})}}{k}\\ & = \frac{\ln{(a)}}{k}\\ \end{align} [/math]

Deceleration

Deceleration is calculated slightly differently. Instead of using k to calculate distance and velocity, it uses j, which is defined as [math]\pagecolor{Black}\color{White}\min(\frac{k}{3},2)[/math]. A different rate of deceleration is used to prevent ships suddenly transitioning from "many, many AU away" to "on grid and out of warp" more rapidly than other pilots (or the server / client) can keep up with.

There is a complication with deceleration calculations. Ships do not drop out of warp at 0 m/s. Instead, they drop out of warp at s m/s, after which normal sub-warp calculations take over.

[math]\pagecolor{Black}\color{White}s = \min(100, v_{subwarp}/2)[/math]

Where v_subwarp is the maximum subwarp velocity of the ship; this varies greatly depending on the ship hull and pilot skills.

Distance

This changes the formulae used slightly. Remember that distance travelled is the integral of velocity.

[math]\pagecolor{Black}\color{White} \begin{align} v & = k * e^{jt}\\ d_{decel} & = \int_{0}^{\infty}k*e^{jt}\,dt = \frac{k*e^{jt}}{j}\\ & = \frac{v}{j} \end{align} [/math]

The distance covered while decelerating from v_warp is

[math]\pagecolor{Black}\color{White} \begin{align} d_{decel} & = \frac{v_{warp}}{j} = \frac{k*a}{j} \end{align} [/math]

Note that for ships that travel at up to 6 AU/s, k / j = k / (k/3) = 3, so these ships cover 3 AU while decelerating. The complication of not stopping warp at 0 can be safely ignored for distance calculations, because the distance that would be covered while decelerating from 100 m/s is insignificant compared to the ~450 billion meters it takes to decelerate from warp speed to warp drop speed.

Time

As with acceleration, time to decelerate from maximum warp velocity is worked out by rearranging the velocity equation.

[math]\pagecolor{Black}\color{White} \begin{align} v &= k*e^{jt}\\ \frac{v}{k} & = e ^ {jt}\\ t & = \frac{\ln{(\frac{v}{k})}}{j} \end{align} [/math]

While the deceleration from s to 0 was insignificant in terms of distance, it is significant in terms of time. This means that the time to decelerate is calculated as follows:

[math]\pagecolor{Black}\color{White} \begin{align} t_{decel} & = t_{decel\_warp} - t_{decel\_s}\\ & = \frac{\ln{(\frac{v_{warp}}{k})}}{j} - \frac{\ln{(\frac{s}{k})}}{j}\\ & = \frac{\ln{(\frac{v_{warp}}{k})} - \ln{(\frac{s}{k})}}{j}\\ & = \frac{\ln{v_{warp}} - \ln{k} - \ln{s} + \ln{k}}{j}\\ & = \frac{\ln{v_{warp}} - \ln{s}}{j}\\ & = \frac{\ln{(\frac{v_{warp}}{s})}}{j} \end{align} [/math]

Cruising

Distance

The distance covered while cruising is the total warp distance minus any distance covered while accelerating or decelerating.

[math]\pagecolor{Black}\color{White}d_{cruise} = d_{total} - d_{accel} - d_{decel}[/math]

For all but the fastest ships, this will be d_total - 4 AU.

Time

This one is easy. Time spent cruising is simply

[math]\pagecolor{Black}\color{White}t_{cruise} = \frac{d_{cruise}}{v_{warp}}[/math]

Short Warps

The above calculations work as long as some time is spent at maximum warp speed. If the warp is short enough that the ship never reaches top speed, a different set of calculations are needed.

[math]\pagecolor{Black}\color{White} \begin{align} d_{accel} & = \frac{v_{max}}{k}, d_{decel} = \frac{v_{max}}{j}\\ d_{total} & = d_{accel} + d_{decel} = v_{max}(\frac{1}{k} + \frac{1}{j})\\ v_{max} & = \frac{d_{total}*k*j}{k + j} \end{align} [/math]

This enables the calculation of new acceleration and deceleration times using the formulae described in the previous sections, but substituting in the new v_max

[math]\pagecolor{Black}\color{White} \begin{align} t_{accel} & = \frac{\ln{(\frac{v_{max}}{k})}}{k}\\ t_{decel} & = \frac{\ln{(\frac{v_{max}}{s})}}{j}\\ t_{total} & = t_{accel} + t_{decel} \end{align} [/math]

Implementation

The following python code is one possible implementation of the above. It attempts to generate the same data as presented by CCP in the forums. It matches with their numbers, except for 50 AU titan warps, which are one second out.

import math
AU_IN_M=149597870700

def get_distance(dist):
    if dist > 1e9:
        return (dist / AU_IN_M, "AU")
    else:
        return (dist/1000, "KM")

# Warp speed in AU/s, subwarp speed in m/s, distance in m
def calculate_time_in_warp(max_warp_speed, max_subwarp_speed, warp_dist):

    k_accel = max_warp_speed
    k_decel = min(max_warp_speed / 3, 2)

    warp_dropout_speed = min(max_subwarp_speed / 2, 100)
    max_ms_warp_speed = max_warp_speed * AU_IN_M

    accel_dist = max_ms_warp_speed / k_accel
    decel_dist = max_ms_warp_speed / k_decel

    minimum_dist = accel_dist + decel_dist

    cruise_time = 0

    if minimum_dist > warp_dist:
        max_ms_warp_speed = warp_dist * k_accel * k_decel / (k_accel + k_decel)
    else:
        cruise_time = (warp_dist - minimum_dist) / max_ms_warp_speed

    accel_time = math.log(max_ms_warp_speed / k_accel) / k_accel
    decel_time = math.log(max_ms_warp_speed / warp_dropout_speed) / k_decel


    total_time = cruise_time + accel_time + decel_time
    distance = get_distance(warp_dist)
    return total_time


distances = [150e3, 1e9, AU_IN_M * 1, AU_IN_M * 2, AU_IN_M * 5, AU_IN_M * 10, AU_IN_M * 20, AU_IN_M * 50, AU_IN_M * 100, AU_IN_M * 200]
speeds = [1.36, 1.5, 2, 2.2, 2.5, 2.75, 3, 3.3, 4.5, 5, 5.5, 6, 8]

result = {}
for speed in speeds:
    for dist in distances:
        result[(dist, speed)] = calculate_time_in_warp(speed, 200, dist)

print("{:9s}".format(""), end="")
for speed in speeds:
    print("{:9.2f}".format(speed), end="")

last_dist = 1e999
for x,y in sorted(result.keys()):
    dist = get_distance(x)
    if (y < last_dist):
        print("\n{:7.5n} {:s}".format(dist[0],dist[1]), end="")
    last_dist = y

    print("{:9.0f}".format(math.ceil(result[x,y])), end="")

print()